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A particle moves along a circle of radius R with a constant angular speed omega. Its displacement(only magnitude)in time t will be


2 years ago

Susmita
425 Points
							Draw a circle.Draw two points A,B on its perimeter.Join A and B by a straight line.Say the length of it is x.We have to find out x.Join A and B with centre of the circle 0.These two lines AO and BO are basically two radius.So each has a length of R.Angular speed$\omega = \frac{d \theta}{dt}$Or,theta=omega×ttheta is angle A0B.Now draw a perpendicular bisector on AB from O.It will divide AB in two segments of length x/2 and divide the angle theta into two equal angle theta/2.From any of the trianglesin(theta/2)=(x/2)/ROr,x=2Rsin(theta/2)=2Rsin(omega×t/2)Please approve the answer in you are helped.

2 years ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions