4(s/a -1)(s/b -1)(s/c -1) = r/R , prove the given equation LHS=RHS.

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Arun · Answer

Dear student LHS can be written as 4(s-a) (s – b) ( s – c) / abc = 4 s (s-a) (s – b) ( s – c) / abc * s = 4 (delta)^2 / abc * s = delta /(s*R) = r/R

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4(s/a -1)(s/b -1)(s/c -1) = r/R , prove the given equation LHS=RHS.

4(s/a -1)(s/b -1)(s/c -1) = r/R , prove the given equation LHS=RHS.

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4(s/a -1)(s/b -1)(s/c -1) = r/R , prove the given equation LHS=RHS.

4(s/a -1)(s/b -1)(s/c -1) = r/R , prove the given equation LHS=RHS.

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