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a(cosA+cosB)=2(a+b)sin^2A/2
question is wrong. It is 2(a+b)sin2(C/2). I solved it.
dude after solving this it comes out 2(a+b)[c2 -(a 2+b2 )]/4ab = 2(a+b)sin2c/2
if u wanna try just put the values of cosA and cosB and then take the LCM and solve.
Well the answer is coming 2(a+b)(c^2-(a-b)^2)/4ab = 2(a+b)sin^2(C/2)
Take the LCM of values of cosa and cosb and then solve. it will come this only
the question might be wrong. pleez check again
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