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2sinA=2-cosA,cosA=2(1-sinA),1-sin2A=4(1-sinA)2
Hi Saurav,
Let SinA = x.
So cosA = (1-x2)1/2.
Hence the eqn, 2x = 2 - (1-x2)1/2.
Or (1-x2)1/2 = 2 - 2x
Squaring, we have, 4+4x2-8x = 1-x2.
or 5x2 - 8x + 3 = 0.
(5x-3)(x-1) = 0.
So x = 1 or x = 3/5
So SinA = 1 or 3/5.
Hope that helps.
All the best.
Regards,
Ashwin (IIT Madras).
3/5 or 1
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