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In a triangle ABC, 2ac sin 1/2 (A – B + C) = (A) a2+b2-c2 (B) c2+a2-b2 (C) b2-c2-a2 (D) c2-a2-b2
A+B+C=Piso A+C = Pi - Bso here it will be : 2ac.sin(Pi/2 -B) = 2ac.cosBby cosine rule, we have: c2+a2-b2 = 2ac cos Boption B--Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficultto understand - post it here and we will get you the answer and detailed solution very quickly.We are allIITians and here to help you in your IIT JEE preparation. All the best.Regards,Ramesh IIT Kgp - 05 batch
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