In a triangle ABC, 2ac sin 1/2 (A – B + C) =
(A) a2+b2-c2 (B) c2+a2-b2
(C) b2-c2-a2 (D) c2-a2-b2
In a triangle ABC, 2ac sin 1/2 (A – B + C) =
(A) a2+b2-c2 (B) c2+a2-b2
(C) b2-c2-a2 (D) c2-a2-b2