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cos3x/cosx= (4cos^3 x-3cosx)/cosx=1/3
=> 4cos^2 x-3=1/3
cos^2 x=5/6
as we know that cos^2 x+sin^2 x=1
so, sin^2 x=1/6
and sin3x/sinx= (3sinx-4sin^3 x)/sinx
=> 3-4sin^2 x=7/3
asnwer>> 7/3
thank you !! but i could solve it.... by the same method after posting it!!
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