Guest

show that a/(c+a-b)+b/(a+b-c)+c/(c+b-a)>=3.if a,b,c are the sides of triangle

show that a/(c+a-b)+b/(a+b-c)+c/(c+b-a)>=3.if a,b,c are the sides of triangle

Grade:12th Pass

1 Answers

Shilpi Suman
46 Points
13 years ago

As we know, in any triangle, the sum of any two sides is greater than the third side.

So, the denominator of all the fractions in the above expression would be positive. Also, if the triangle is an equilateral one, then the value of the given expression would be 3 (and that's the minimum value).

In any other case, the value would exceed 3. You can check this by taking random values for three sides of a triangle-  for instance (2,4,6) or (3,4,5).

Think You Can Provide A Better Answer ?

ASK QUESTION

Get your questions answered by the expert for free