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solve 4 x

sinx+cosx+cosecx+secx+tanx+cotx=-7

Sagnik Mukhopadhyay , 15 Years ago
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anser 1 Answers
vikas askiitian expert

sinx+cosx+secx+cosecx+cotx+tanx=7

 sinx+cosx+1/cosx +sinx/cosx +1/sinx +cosx/sinx=7

sinx+cosx+1+sinx/cosx  +1+cosx/sinx=7

sinx+cosx+1+sinx+cosx/sinxcosx=7

sinx+cosx+2(1+sinx+cosx)/sin2x=7

                                                           (sinx+cosx)square=1+sin2x

 we get

    root(1+sin2x)+2(1+(1+sin2x))/sin2x=7

                                                             put sin2x=t

   we get t=0 on solving

     sin2x=0

    x=npie

 

 

 

Last Activity: 15 Years ago
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