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1.Prove that sin(3x) = 4sinx.sin2x.sin4x

2.Solve : cosx(1+sin x/4 - 2cosx) + sinx (cosx/4 - 2sinx) = 0

3.solve : cos 3x + cos 2x = sin 3x/2 + sin x/2 , x=(0,pi)

4.solve for x and y : cos2x + cosx.cosy + cos2y = 0

Please solve quickly

manoj jangra , 15 Years ago
Grade 12
anser 2 Answers
Sham Singh Namdhari

Last Activity: 8 Years ago

4sinx*sin2x*sin4x=sin3x LHS= 2(cosx-cos3x)sin4x= sin5x+sin3x-sin7x-sinx=sin3x So, sin5x-sin7x=sinx or, -2cos6x*sinx=sinx so, either sinx=0 or cos6x=-1/2 so, x= n*pi or x=(2n*pi+/- 2*pi/3)/6 where n is any integer

ayisha

Last Activity: 5 Years ago

2(2sinx.sin2x).sin4x=sin3x
2(cosx-cos3x0.sin4x=sin3x
2cosxsin4x-2cos3xsin4x=sin3x
2sin4xcosx-2sin4xcos3x=sin3x
sin5x+sin3x-(sin7x+sinx)=sinx
sin5x-sin7x=sinx
2cos6xsin(-x)=sinx
-2cos6xsinx=sinx
-2cos6xsinx-sinx=0
sinx=0 or cos6x =-1/2
x=npie

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