1-tan^2 45°/1+tan^2 45° = (A) tan 90° (B) 1 (C) sin 45° (D) 0

Question

Harshit Singh · Answer

Dear Student

Option (D) is correct.

Substitute the of tan 45° in the given equation

tan 45° = 1
1-tan^2 45°/1+tan^2 45° = (1-1^2)/(1+1^2)

= 0/2
= 0
The solution of the above equation is 0.

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1-tan^2 45°/1+tan^2 45° = (A) tan 90° (B) 1 (C) sin 45° (D) 0

1-tan^2 45°/1+tan^2 45° =
(A) tan 90° (B) 1 (C) sin 45° (D) 0

1 Answers

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1-tan^2 45°/1+tan^2 45° = (A) tan 90° (B) 1 (C) sin 45° (D) 0

1-tan^2 45°/1+tan^2 45° =(A) tan 90° (B) 1 (C) sin 45° (D) 0

1 Answers

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1-tan^2 45°/1+tan^2 45° =
(A) tan 90° (B) 1 (C) sin 45° (D) 0