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1-tan^2 45°/1+tan^2 45° = (A) tan 90° (B) 1 (C) sin 45° (D) 0
Dear StudentOption (D) is correct.Substitute the of tan 45° in the given equationtan 45° = 11-tan^2 45°/1+tan^2 45° = (1-1^2)/(1+1^2)= 0/2= 0The solution of the above equation is 0.Thanks
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