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1. If A + B = 45° then (1+ tanA)(1+ tanB)= 2. Let A and B be such that π
Dear Ayushi tan (A + B) = tan 45 = tan A + tanB / 1 – tanA tanB 1 – tan A tanB = tan A + tanB 1 + 1 = 1 + tan A + tan B + tanA tanB 2 = (1 + tanA) (1 + tanB) RegardsArun
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