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```
(1+cos180/8) (1+cos540/8) (1+cos900/8) (1+cos1260/8) is equal to ??

```
3 years ago

shivamverma
19 Points
```							you can write (cos 900/8 )as (– cos 540/8)   and cos 1260/8) as ( -cos 180/8)  so  the original equation will become (1+cos 180/8) ( 1-cos 180/8) (1+cos 540/8)(1 -cos 540/8)  upon further simplification you will get ( sin^2 180/8 )( sin^2 540/8)then multiply and divide it by 4 it will become ¼ x[( 2 . sin 180/8 . sin 540/8 )]^2then use formulae of  2 sin A . sin B = cos [A-B]  –  cos [A+B]and you will get ¼ x [cos 45-cos90]^2    which is equal to ¼ x 1/2=1/8 SO 1/8 IS THE REQUIRED ANSWER!!
```
3 years ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions