In a triangle ABC, medians AD and CE are drawn. If AD=5, angle DAC= π/8 and angle ACE=π/4, then the area of the triangle ABC is (5a/b). What is the value of (a+b)?

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In a triangle ABC, medians AD and CE are drawn. If AD=5, angle DAC= π/8 and angle ACE=π/4, then the area of the triangle ABC is (5a/b). What is the value of (a+b)?

In a triangle ABC, medians AD and CE are drawn. If AD=5, angle DAC=π/8 and angle ACE=π/4, then the area of the triangle ABC is (5a/b). What is the value of (a+b)?

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In a triangle ABC, medians AD and CE are drawn. If AD=5, angle DAC= π/8 and angle ACE=π/4, then the area of the triangle ABC is (5a/b). What is the value of (a+b)?

In a triangle ABC, medians AD and CE are drawn. If AD=5, angle DAC=π/8 and angle ACE=π/4, then the area of the triangle ABC is (5a/b). What is the value of (a+b)?

1 Answers

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