# Find the area bounded by the curves y = x|x| , x - axis , x = 1 & x = -1.

Parvez ali
askIITians Faculty 47 Points
9 years ago

Thanks & Regards
Parvez Ali

Sher Mohammad IIT Delhi
askIITians Faculty 174 Points
9 years ago
y=x^2 for x>0
y=-x^2 for x<0

$\int_{-1}^0 -x^2 \, dx+\int_{0}^1 -x^2 \, dx=\frac{-1}{3}+\frac{1}{3}=0$

if we are just checking the magnitude of area,

$|\int_{-1}^0 -x^2 \, dx|+\int_{0}^1 -x^2 \, dx=\frac{1}{3}+\frac{1}{3}=2/3$

B.tech, IIT Delhi

bharat bajaj IIT Delhi
askIITians Faculty 122 Points
9 years ago
Area bounded :
Integral ofy = x|x| , limits -1 to 1
It should be divided in two parts , -1 to 0 and 0 to 1
Integral 1= -x^2 , -1 to 0 = 1/3
Integral 2= x^2 , 0 to 1 = 1/3
Total area bounded : 2/3 sq. units
Thanks & Regards
Bharat Bajaj
IIT Delhi