#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# Find the area bounded by the curves y = x|x| , x - axis , x = 1 & x = -1.

Parvez ali
7 years ago

Thanks & Regards
Parvez Ali

7 years ago
y=x^2 for x>0
y=-x^2 for x<0

$\int_{-1}^0 -x^2 \, dx+\int_{0}^1 -x^2 \, dx=\frac{-1}{3}+\frac{1}{3}=0$

if we are just checking the magnitude of area,

$|\int_{-1}^0 -x^2 \, dx|+\int_{0}^1 -x^2 \, dx=\frac{1}{3}+\frac{1}{3}=2/3$

B.tech, IIT Delhi

bharat bajaj IIT Delhi
7 years ago
Area bounded :
Integral ofy = x|x| , limits -1 to 1
It should be divided in two parts , -1 to 0 and 0 to 1
Integral 1= -x^2 , -1 to 0 = 1/3
Integral 2= x^2 , 0 to 1 = 1/3
Total area bounded : 2/3 sq. units
Thanks & Regards
Bharat Bajaj
IIT Delhi

26 Points
7 years ago

0
Thanks & Regards