# An insurance company insures 4000people against loss of both eyes in a caraccident. Based on previous data, the rates were computed on the assumptionthat on the average10persons in100000will have car accident each yearthat result in this type of injury. What is the probability that more than 3 of theinsured will collect on their policy in a given year?

Md Mushahid
21 Points
2 years ago
Number of deaths from a disease.
No. of suicides reported in a city.
No. of printing mistakes at each page of a book.
No. of telephone calls per minute at a small business.
No. of paint spots per new automobile.
No. of arrivals at a toll booth
No. of flaws per bolt of cloth
Rahul kumar
13 Points
one year ago
use possion distribution

here probability of person to get injuery of such kind p = 10/100000
n = 4000
mean = m =  np = 4000X(10/100000) = 0.4

p(x) = e-m.mx / x!

put x = 0,1,2

then add all the values and subtract it from 1

DEVAVRAT SINGH
25 Points
3 months ago
We can use formula of
P(r>=n)=1-p(r
So for more than 2 persons
P(r>=2)=1-p(r
=1-p(0)+p(1)
since m=0.4
So,p(r)=(e^-m*m^r)/r!
P(r>=2)=0.007926