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Grade 12th passTop Engineering Colleges in India

An insurance company insures 4000
people against loss of both eyes in a car
accident. Based on previous data, the rates were computed on the assumption
that on the average10
persons in100000
will have car accident each year
that result in this type of injury. What is the probability that more than 3 of the
insured will collect on their policy in a given year?

Profile image of BRAJKUMAR
8 Years agoGrade 12th pass
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3 Answers

Profile image of Md Mushahid
6 Years ago
Number of deaths from a disease.
No. of suicides reported in a city.
No. of printing mistakes at each page of a book.
Emission of radioactive particles.
No. of telephone calls per minute at a small business.
No. of paint spots per new automobile.
No. of arrivals at a toll booth
No. of flaws per bolt of cloth
Profile image of Rahul kumar
5 Years ago
use possion distribution 
 
here probability of person to get injuery of such kind p = 10/100000
n = 4000
mean = m =  np = 4000X(10/100000) = 0.4
 
p(x) = e-m.mx / x!
 
put x = 0,1,2 
 
then add all the values and subtract it from 1 
 
that’s your answer
Profile image of DEVAVRAT SINGH
4 Years ago
We can use formula of 
P(r>=n)=1-p(r
So for more than 2 persons
P(r>=2)=1-p(r
            =1-p(0)+p(1)
          since m=0.4
          So,p(r)=(e^-m*m^r)/r!
      P(r>=2)=0.007926