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Work done in converting 1 gram of ice at -10C into steam at 100C is ? A 3045 J B 6056J C 721 J

Work done in converting 1 gram of ice at -10C into steam at 100C is ? 
A 3045 J 
B 6056J 
C 721 J 

Grade:12

1 Answers

Norman Manchu
151 Points
6 years ago
m=1gram
The change takes place as-
-10°C(ice)---0°C(ice)---0°C(water)---100°C(water)---100°C(steam)
Tip:When state changes temperature doesn't Use energy=ms?(theta) when temperature changes and energy=mL when the state changes
-10°C(ice)to 0°C(water)=ms?(theta)=5cal
0°C(ice)to 0°C(water)=mL=80cal
0°C(water)to 100°C(water)=100cal
100°C(water)to 100°C(steam)=540cal
Total=725cal=3045joules
Note:1cal=4•2joules|||
Latent heat of ice to water=80cal
Latent heat of water to stean=540cal
Specific heat of ice=0•5cal-per-gram
Specific heat of water=1cal-per-gram
Done|

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