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If you see from the first law of thermodynamics,
del Q=dU+del W
where
Q is heat interaction, U is internal energy and W is the work done.
For a closed system,
del Q= dU+ PdV …..(1)
As we know from the definition of enthalpy,
H=U+PV
For change in enthalpy for constant pressure,
dH=dU+PdV ….(2)
So comparing the equations 1 and 2 we get,
del Q= dH
So, change in enthalpy is equal to heat interaction for a constant pressure process.
Regards
Arun (askIITians forum expert)
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