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When the temperature of a gas is raised from 27`c to 90`c the percentage increase in the ram velocity of molecular When the temperature of a gas is raised from 27`c to 90`c the percentage increase in the ram velocity of molecular
Vrms = √(3RT / Mo) i.e. Vrms ∝ √T T1 = 27°C = 27 + 273 = 300K T2 = 90°C = 90 + 273 = 363K ∴ {Vrms2 / Vrms1} = √(T2 / T1) = √(363 / 300) = 1.1 % increase in rms velocity = {(Vrms2 – Vrms1) / (Vrms1)} × 100 = {(1.1 – 1) / 1} × 100 = 0.1 × 100 % increase in rms velocity = 10%
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