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When temperature of a gas, contained in a closed vessel is increased by 5`C, it`s pressure increases by 1%. The original temperature of gas was approximately:

When temperature of a gas, contained in a closed vessel is increased by 5`C, it`s pressure increases by 1%. The original temperature of gas was approximately:

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Grade:11

2 Answers

Arun
25763 Points
3 years ago
As vessel is closed , so volume of the container is constant.
P proportional to T
where P = pressure 
and T= temperature
so,
P1/P2 = T1/T2
T2/T1 = P2/P1
T2/T1  -1 = P2/P1  -1
T2 -T1/T1 = P2 -P1/P1
(5/T1)*100 = 1
T1 = 500°c
 
Regards
Arun (askIITians forum expert)
Piyush Upadhyay
34 Points
3 years ago
There is a little correction the answer is 500K or 227`C. You forgot that we have assumed T1 and T2 to be absolute temperatures 😄😦😳😱

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