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Grade: 11
        
What will be the temperature when the rms velocity is double of that at 300k?
 
7 months ago

Answers : (2)

Arun
23520 Points
							

 V_{rms} = \sqrt{\frac{3RT}{M}}

\Rightarrow V_{rms}\ \propto\ \sqrt{T}

V_{rms}  will be doubled when temperature increases four times.

\therefore  Temperature = 4 \times initial temperature

                           = 1200 K

 

Hope it helps

7 months ago
Khimraj
3008 Points
							

Let the initial and final velocities be u and v respectively.

Since v and u are propotional to √T

v/u = √T(final)/√T(initial) = 2

Squaring on both sides, 4=T(final)/T(initial)

T(initial) = 300 K

Therefore T(final) = 4 × 300 = 1200 K

6 months ago
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