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What will be the temperature when the rms velocity is double of that at 300k?

What will be the temperature when the rms velocity is double of that at 300k?
 

Grade:11

2 Answers

Arun
25758 Points
2 years ago

 V_{rms} = \sqrt{\frac{3RT}{M}}

\Rightarrow V_{rms}\ \propto\ \sqrt{T}

V_{rms}  will be doubled when temperature increases four times.

\therefore  Temperature = 4 \times initial temperature

                           = 1200 K

 

Hope it helps

Khimraj
3007 Points
2 years ago

Let the initial and final velocities be u and v respectively.

Since v and u are propotional to √T

v/u = √T(final)/√T(initial) = 2

Squaring on both sides, 4=T(final)/T(initial)

T(initial) = 300 K

Therefore T(final) = 4 × 300 = 1200 K

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