van der waals b for oxygen is 32 cm^3/mol.compute diameter of an o2 molecule?

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Arun · Answer

b=4V m ​ =32cm 3 /mol V m ​ =8cm 3 /mol For one molecule, V= 6.023×10 23 molecules/mol 8cm 3 /mol ​ V=1.33×10 −23 cm 3 /molecule But V= 3 4 ​ πr 3 3 4 ​ πr 3 =1.33×10 −23 cm 3 /molecule r 3 =3.17×10 −24 cm 3 /molecule r=1.47×10 −8 cm The diameter of an O 2 ​ molecule =2r=2×1.47×10 −8 cm=2.94×10 −8 cm

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van der waals b for oxygen is 32 cm^3/mol.compute diameter of an o2 molecule?

van der waals b for oxygen is 32 cm^3/mol.compute diameter of an o2 molecule?

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