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```
van der waals b for oxygen is 32 cm^3/mol.compute diameter of an o2 molecule?

```
8 months ago

Arun
25768 Points
```							b=4V m​  =32cm 3 /molV m​  =8cm 3 /mol For one molecule, V= 6.023×10 23 molecules/mol8cm 3 /mol​  V=1.33×10 −23 cm 3 /moleculeBut V= 34​  πr 3 34​  πr 3 =1.33×10 −23 cm 3 /moleculer 3 =3.17×10 −24 cm 3 /moleculer=1.47×10 −8 cmThe diameter of an O 2​   molecule =2r=2×1.47×10 −8 cm=2.94×10 −8 cm
```
8 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions