MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 9
        
Two simple harmonic motions are represented  by equation  y1=10sin (4×22÷7t+22÷7÷4)and y2=5 (sin 322÷7t+root3cos322÷7t).their amplitudes are in what ratio
10 months ago

Answers : (1)

Arun
14776 Points
							
Dear student
 
y1 = 10 sin (4*pi*t + pi/4)
y2 = 5 sin 3*pi*t + sqrt(3) cos 3*pi*t
y2 = \sqrt34 sin (3*pi*t + @) 
 Hence ratio of amplitude of y1 and y2
 = 10/\sqrt34
 
Regards
Arun (askIITians forum expert)
10 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 276 off

COUPON CODE: SELF10


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 297 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details