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Two simple harmonic motions are represented by equation y 1=10sin (4×22÷7t+22÷7÷4)and y 2=5 (s in 322÷7t+root3cos322÷7t).their amplitudes are in what ratio

Two simple harmonic motions are represented  by equation  y1=10sin (4×22÷7t+22÷7÷4)and y2=5 (sin 322÷7t+root3cos322÷7t).their amplitudes are in what ratio

Grade:9

2 Answers

Arun
25750 Points
6 years ago
Dear student
 
y1 = 10 sin (4*pi*t + pi/4)
y2 = 5 sin 3*pi*t + sqrt(3) cos 3*pi*t
y2 = \sqrt34 sin (3*pi*t + @) 
 Hence ratio of amplitude of y1 and y2
 = 10/\sqrt34
 
Regards
Arun (askIITians forum expert)
Kushagra Madhukar
askIITians Faculty 628 Points
3 years ago
Dear student,
Please find the solution to your problem.
 
y1 = 10 sin (4πt + π/4)
y2 = 5 sin 3πt + √3 cos 3πt
y2 = √34 sin (3πt + @) 
 Hence ratio of amplitude of y1 and y2
 = 10/√34
 
Thanks and regards,
Kushagra

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