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Two identical metal balls, one at T1=300 K and the other at T2=600 K are kept
at a distance of 1 m in vacuum. Will the temperatures equalize by radiation? Will
the rate of heat gained by the colder sphere be proportional to T24-T14 as may be
expected from the Stefan’s law?

dhananjay shimpi , 10 Years ago
Grade
anser 1 Answers
Askiitians Tutor Team

To address your question about the two metal balls at different temperatures, we need to delve into the principles of thermal radiation and the Stefan-Boltzmann law. Yes, the temperatures of the two balls will eventually equalize due to radiation, but the rate of heat transfer will not be directly proportional to T^4 - T^4 as one might initially expect. Let's break this down step by step.

Understanding Thermal Radiation

Thermal radiation is the process by which objects emit energy in the form of electromagnetic waves due to their temperature. All objects emit radiation, and the amount of energy radiated increases significantly with temperature. The Stefan-Boltzmann law quantifies this relationship, stating that the power radiated per unit area of a black body is proportional to the fourth power of its absolute temperature:

  • P = σT^4

where P is the power radiated, σ is the Stefan-Boltzmann constant (approximately 5.67 x 10^-8 W/m²K^4), and T is the absolute temperature in Kelvin.

Heat Transfer Between the Balls

In your scenario, we have two identical metal balls: one at 300 K and the other at 600 K. The ball at 600 K will radiate more energy than it absorbs from the 300 K ball, while the 300 K ball will absorb energy from the hotter ball. This process will continue until thermal equilibrium is reached, meaning both balls will eventually have the same temperature.

Rate of Heat Transfer

Now, regarding the rate of heat gained by the colder sphere, it is important to note that the heat transfer is not simply a matter of subtracting the fourth powers of their temperatures. The heat transfer rate (Q) from the hotter ball to the colder ball can be expressed as:

  • Q = σA(T_hot^4 - T_cold^4)

Here, A is the surface area of the balls, T_hot is the temperature of the hotter ball (600 K), and T_cold is the temperature of the colder ball (300 K). This equation shows that the rate of heat transfer depends on the difference in the fourth powers of their temperatures, not just the difference itself.

Implications of the Stefan-Boltzmann Law

From the equation, we can see that as the temperatures of the balls approach each other, the rate of heat transfer will decrease. Initially, when the temperature difference is large, the rate of heat transfer will be significant. However, as the colder ball gains heat and its temperature rises, the difference in the fourth powers will diminish, leading to a slower rate of heat transfer.

Conclusion

In summary, the two metal balls will indeed equalize their temperatures through radiation. However, the rate at which the colder ball gains heat is governed by the difference in the fourth powers of their temperatures, as described by the Stefan-Boltzmann law. This nuanced understanding of thermal radiation helps clarify the dynamics of heat transfer in this scenario.

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