two identical masses of 5 kg each fall on a wheel on a height of 10m. The wheel disturb the mass of 2kg water, then the rises in temperature will be what

Question

Arun · Answer

Dear Goutam W = J Q 2m * g* h = J * m' * Cp * Delta T 2 *5*10*10 = 4.2 *(2* 1000* delta T) Delta T = 0.12&deg;c Regards Arun (askIITians forum expert)

Rishi Sharma · Answer

Dear Student, Please find below the solution to your problem. W = J Q 2m * g* h = J * m' * Cp * Delta T 2 *5*10*10 = 4.2 *(2* 1000* delta T) Delta T = 0.12&deg;c Thanks and Regards

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two identical masses of 5 kg each fall on a wheel on a height of 10m. The wheel disturb the mass of 2kg water, then the rises in temperature will be what

two identical masses of 5 kg each fall on a wheel on a height of 10m. The wheel disturb the mass of 2kg water, then the rises in temperature will be what

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