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Let a, b and c be the specific heat capacities of liquids A, B and C.
Let the mass of the liquids be m.
When A and B are mixed:
m* a (16-12) = m*b(19- 16)
4a = 3b
When B and C are mixed:
mb (23-19) = mc (28-23)
4b = 5c
Therefore, 16a = 12b = 15c
Let x be the temperature when A and C are mixed
ma (x -12) = mc (28- x)
a/c = 15/16 = (28-x)/(x-12)
15x - 180 = 448 -16x
31x = 628
x = 20.25 degree
Regards
Arun (askIITians forum expert)
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