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Grade 11Thermal Physics

the temperature of an ideal gas varies with its volume (v) as T= -aV*V*V + b*V*V . where a and b are positive constants . The maximum pressure during this process is ?

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8 Years agoGrade 11
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ApprovedApproved Tutor Answer1 Year ago

To find the maximum pressure of the ideal gas given the temperature-volume relationship \( T = -aV^3 + bV^2 \), we need to use the ideal gas law, which states that \( PV = nRT \). Here, \( P \) is pressure, \( V \) is volume, \( n \) is the number of moles, \( R \) is the ideal gas constant, and \( T \) is the temperature. Since we have an expression for temperature in terms of volume, we can substitute that into the ideal gas law to express pressure as a function of volume.

Step-by-Step Calculation

First, let's rewrite the ideal gas law using the provided temperature equation:

  • From the ideal gas law: \( P = \frac{nRT}{V} \)
  • Substituting for \( T \): \( P = \frac{nR(-aV^3 + bV^2)}{V} \)
  • This simplifies to: \( P = nR(-aV^2 + bV) \)

Finding the Maximum Pressure

To find the maximum pressure, we need to differentiate the pressure function with respect to volume and set the derivative equal to zero. This will help us find the critical points where pressure could be maximized.

  • Differentiate \( P \):
    • Using the product rule, we have \( \frac{dP}{dV} = nR(-2aV + b) \)
  • Set the derivative equal to zero to find critical points:
    • Setting \( -2aV + b = 0 \) gives us \( V = \frac{b}{2a} \)

Calculating Maximum Pressure

Now that we have the volume at which pressure is maximized, we can substitute \( V = \frac{b}{2a} \) back into the pressure equation:

  • Substituting into \( P \):
    • First, calculate \( P \) at this volume:
      • Substituting \( V \) into \( P \):
        • \( P = nR\left(-a\left(\frac{b}{2a}\right)^2 + b\left(\frac{b}{2a}\right)\right) \)
        • \( = nR\left(-a\frac{b^2}{4a^2} + \frac{b^2}{2a}\right) \)
        • \( = nR\left(-\frac{b^2}{4a} + \frac{2b^2}{4a}\right) \)
        • \( = nR\left(\frac{b^2}{4a}\right) \)

Final Expression for Maximum Pressure

Thus, the maximum pressure during this process can be expressed as:

P_{max} = \frac{nRb^2}{4a}

This result shows that the maximum pressure depends on the number of moles of gas, the ideal gas constant, and the constants \( a \) and \( b \) from the temperature-volume relationship. Understanding how these variables interact helps us grasp the behavior of gases under varying conditions.