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The ratio of energies of emitted radiations of a black body at 27 degree celsius and 927 degree celsius.

shashi singh , 8 Years ago
Grade 12th pass
anser 1 Answers
Adarsh
Dear Shashi ,
Energy radiated , E = k.e.A.T4   where k is stefan constant , e is emmisivity , A is area , T is temp. 
In both case black body are identical so ratio of energies radiated = 3004/12004 = 1 : 256 ..
Thanks and Regards
Adarsh
Last Activity: 8 Years ago
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