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THE RATE AT WHICH RADIANT ENERGY REACHES THE EARTH'S SURFACE FROM SUN IS ABOUT 1.4 kW/m^2.



The distance from earth to sun is approximately and the radius of Sun is about .


1)What is the rate of radiation of energy per unit area from Sun's surface???????



2)If the sun radiates as an ideal black body what is temperature of its surface???????

Shane Macguire , 12 Years ago
Grade upto college level
anser 1 Answers
Askiitians Tutor Team

To tackle your questions about the Sun's radiation, we can break it down into two parts: first, calculating the rate of energy radiation per unit area from the Sun's surface, and second, determining the surface temperature of the Sun assuming it behaves like an ideal black body.

1. Rate of Radiation of Energy from the Sun's Surface

The rate at which radiant energy reaches the Earth's surface is known as the solar constant, which is approximately 1.4 kW/m². To find the rate of radiation from the Sun's surface, we can use the inverse square law of radiation. This law states that the intensity of radiation from a point source decreases with the square of the distance from the source.

Let's denote:

  • I: Intensity at Earth's surface (1.4 kW/m²)
  • d: Distance from the Earth to the Sun (approximately 1.496 x 1011 meters)
  • R: Radius of the Sun (approximately 6.96 x 108 meters)

The total power radiated by the Sun can be calculated using the formula:

P = I × 4πd²

Substituting the values:

P = 1.4 kW/m² × 4π(1.496 x 1011 m)²

Calculating this gives:

P ≈ 3.846 x 1026 watts

Now, to find the rate of radiation per unit area from the Sun's surface, we can use the formula:

Rate of radiation per unit area = P / (4πR²)

Substituting the values:

Rate = (3.846 x 1026 watts) / (4π(6.96 x 108 m)²)

This calculation yields:

Rate ≈ 6.36 x 107 watts/m²

2. Surface Temperature of the Sun as an Ideal Black Body

To find the surface temperature of the Sun, we can apply the Stefan-Boltzmann Law, which relates the power radiated by a black body to its temperature:

P = σA(T4)

Where:

  • P: Total power radiated (3.846 x 1026 watts)
  • σ: Stefan-Boltzmann constant (approximately 5.67 x 10-8 W/m²K4)
  • A: Surface area of the Sun (4πR²)
  • T: Temperature in Kelvin

First, we calculate the surface area of the Sun:

A = 4π(6.96 x 108 m)²

Now substituting into the Stefan-Boltzmann equation:

3.846 x 1026 W = 5.67 x 10-8 W/m²K4 × 4π(6.96 x 108 m)² × T4

Solving for T gives:

T ≈ 5778 K

This temperature is consistent with the commonly accepted value for the Sun's surface temperature. Thus, the Sun radiates energy at a rate of approximately 6.36 x 107 watts/m², and if it behaves like an ideal black body, its surface temperature is around 5778 K.

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