Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

the outer faces of rectangular slab made up of equal thickness of iron and brass are maintained at 100 degree and 0 degree celcius given the thermal conductivities of iron and brass are 0.2 and 0.3 respectively. how to find the temperature at the interface?

the outer faces of rectangular slab made up of equal thickness of iron and brass are maintained at 100 degree and 0 degree celcius given the thermal conductivities of iron and brass are 0.2 and 0.3 respectively. how to find the temperature at the interface?
 

Grade:11

1 Answers

GURIYA GUPTA
15 Points
2 years ago
Rate of flow of heat energy through iron=rate of flow of heat energy through brass
KA(dT)/l= KA(dT)/l
As Area and length are same, therfore,
0.2(100-T)=0.3(T-0)
20-0.2T=0.3T
T=20/0.5
T=40°C

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free