The observed molecular weight of N2O4 is 80g mol at 350k the percentage of dissociation of N2O4 at 350 k

Question

Umakant biswal · Answer

@ sashikala
kc=[C6H6]/[C2H2]^3.
4=[C6H6]/[0.5]^3
C6H6=O.5 M
N2O4 gives 2NO2
so, 0.5 M will be nearly equal to 15 percent
15 percent will turns out to be the correct answer here .
HOPE IT CLEARS
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The observed molecular weight of N2O4 is 80g mol at 350k the percentage of dissociation of N2O4 at 350 k

The observed molecular weight of N2O4 is 80g mol at 350k the percentage of dissociation of N2O4 at 350 k

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