Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
The molar heat capacity of silver, measured at atmospheric pressure, is found to vary with temperature between 50 and 100 K by the empirical equation C = 0.318T – 0.00109T 2 – 0.628,where C is in J/mol . K and T is in K. Calculate the quantity of heat required to raise 316 g of silver from 50.0 to 90.0 K. the molar mass of silver is 107.87 g/mol.
To obtain Q, substitute 0.318T – 0.00109T2 -0.628 for C in the equation Q = n ∫ CdT, we get,Q = n ∫90 K50 K CdT = n [(0.318 J/mol.K2) T2/2 – (0.00109 J/mol.K3) T3/3 –(0.628 J/mol.K)T] 90 K50 K= n (645.8 J/mol)As the molar mass of silver is 107.87 g/mol, thus the quantity of heat required to raise 316 g of silver from 50.0 to 90.0 K will be,Q = n (645.8 J/mol) = [316 g/(107.87 g/mol)] (645.8 J/mol) =189 JFrom the above observation we conclude that, the quantity of heat required to raise 316 g of silver from 50.0 to 90.0 K would be 189 J.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -