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Grade 9Thermal Physics

The displacement of a particle in SHM varies according to the relation x=4 (cos22÷7t+sin22÷7t)the amplitude of the particle

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vaangmai sriram

8 Years agoGrade 9

1 Answer

Arun

8 Years ago

Displacement = 4 ( cos pi*t + sin li*t)

= 4 $\sqrt$ 2 [(1/ $\sqrt$ 2) cos pi*t + (1/ $\sqrt$ 2) sin pi*t]

= 4 $\sqrt$ 2 sin (pi/4 +t )

Hence amplitude = 4 $\sqrt$ 2

Regards

Arun (askIITians forum expert)

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