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The displacement of a particle in SHM varies according to the relation x=4 (cos​22÷7t+sin22÷7t)the amplitude of the particle

vaangmai sriram , 7 Years ago
Grade 9
anser 1 Answers
Arun

Last Activity: 7 Years ago

Displacement = 4 ( cos pi*t + sin li*t)
= 4\sqrt2 [(1/\sqrt2) cos pi*t + (1/\sqrt2) sin pi*t]
= 4\sqrt2 sin (pi/4  +t )
Hence amplitude = 4\sqrt2
 
Regards
Arun (askIITians forum expert)
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