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Take, bulk modulus of water B 2100 MPa. What increase in pressure is required to decrease the volume of 200 liters of water by 0.004 percent?

Saurabh , 6 Years ago
Grade 12th pass
anser 1 Answers
Arun

Last Activity: 6 Years ago

We have

B = -V dP/dV

=> dP = -B dV/V = - 2.1*109 * (-0.004/200)

= 4.2  * 10Pa

 

Regards

Arun (askIITians forum expert)

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