steam at 100C is passed into a 20g of water at 10C. when water aquires a temp. of 80C the mass of water present will be??

Question

suryathejass · Answer

heat gained =heat lostmL(v) +mS(w)dt =m(w)S(w)dtm×540+m×1×(100-80) =20×1×(80-10)540m+20m = 1400m=2.5therefore total mass of water =20 + 2.5 =22.5g

Rishi Sharma · Answer

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steam at 100C is passed into a 20g of water at 10C. when water aquires a temp. of 80C the mass of water present will be??

steam at 100C is passed into a 20g of water at 10C. when water aquires a temp. of 80C the mass of water present will be??

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steam at 100C is passed into a 20g of water at 10C. when water aquires a temp. of 80C the mass of water present will be??

steam at 100C is passed into a 20g of water at 10C. when water aquires a temp. of 80C the mass of water present will be??

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