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Grade 11Thermal Physics

Show that if α is dependent on the temperature T, then
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Where L0 is the length at the reference temperature T0

Profile image of Radhika Batra
11 Years agoGrade 11
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1 Answer

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ApprovedApproved Tutor Answer11 Months ago

To demonstrate how the length of a material changes with temperature, we need to delve into the concept of thermal expansion. When a material is heated, its particles gain energy and move more vigorously, causing the material to expand. This relationship can be expressed mathematically, particularly when we consider the coefficient of linear expansion, denoted as α.

Understanding Linear Expansion

The linear expansion of a material can be described by the formula:

L = L0 + L0α(T - T0)

In this equation:

  • L is the length of the material at temperature T.
  • L0 is the original length of the material at the reference temperature T0.
  • α is the coefficient of linear expansion, which indicates how much the length changes per degree change in temperature.
  • T is the current temperature, and T0 is the reference temperature.

Dependence of α on Temperature

When we say that α is dependent on temperature, it means that the coefficient of linear expansion can change as the temperature varies. This is particularly relevant for materials that exhibit non-linear thermal expansion behavior, such as metals at high temperatures or polymers.

To express this dependency mathematically, we can modify our initial equation to account for the fact that α is a function of temperature:

L = L0 + L0α(T) (T - T0)

Here, α(T) indicates that the coefficient of linear expansion is now a function of the temperature T. This means that as the temperature changes, the rate at which the length changes also varies.

Example of Temperature Dependence

Let’s consider a practical example. Imagine a metal rod that has a length of 1 meter at a reference temperature of 20°C. If the coefficient of linear expansion α at this temperature is 0.000012 /°C, and we want to find the length of the rod at 100°C, we can use the formula:

L = 1 + 1 × 0.000012 × (100 - 20)

Calculating this gives:

L = 1 + 1 × 0.000012 × 80 = 1 + 0.00096 = 1.00096 meters

Now, if we consider that the coefficient α might change at higher temperatures, say it increases to 0.000015 /°C at 100°C, we would need to recalculate:

L = 1 + 1 × 0.000015 × (100 - 20)

This results in:

L = 1 + 1 × 0.000015 × 80 = 1 + 0.0012 = 1.0012 meters

Conclusion on Length Change

Thus, we see that if α is dependent on temperature, the length of the material will not only change due to the temperature difference but also due to the varying coefficient of linear expansion. This relationship highlights the importance of understanding material properties in engineering and physics, especially when dealing with temperature fluctuations.