Searches related to a liquid cooled from 60 c-40 c in 10 minutes what is the temperature of the liquid in next 10 minutes given the temperature of the surroundings is 5c

T1=60°c T2=40°cTime given(t)= 10 minsGiven Temp(T°)= 5°c By applying the formula:∆T/∆t= k[(T1+T2/2) - T°]We get k= 2/45 And further solving,Applying the same formula,We get Final temperature after 10 mins:= 27.27°C