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Question:A glass tube of uniform bore and length 133cm is to be filled with mercury so that the volume of the tube above the mercury level remains same at all temperatures.Calculate the length of the mercury column .Given gamma glass=2.6*10^-5/degree celcius and gamma mercury =1.82*10^-5/degree celcius ?

Question:A glass tube of uniform bore and length 133cm is to be filled with mercury so that the volume of the tube above the mercury level remains same at all temperatures.Calculate the length of the mercury column .Given gamma glass=2.6*10^-5/degree celcius and gamma mercury =1.82*10^-5/degree celcius ?

Grade:12th pass

2 Answers

Jitendar mishra
13 Points
4 years ago
Gamma of glass × lenght of glass = gamma of Mercury × length of Mercury And . 19 cm Ok any other questions
Guru Yash
26 Points
one year ago
As level is same at all temperature so,
∆L of glass =∆L of mercury
We are given  gamma of both but for linear expansion we consider alpha
We know , gamma =3alpha
 
Let's apply
 
∆L(g)=∆L(Hg)
L * alpha(g)*∆T=L' * alpha(Hg)*∆T
 L*alpha(g)=L' * aplha(Hg)
133 * 3 * 2.6*10^-5 = L' *3*18.2*10^-5
L' = 19 cm

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