plz help.Conceptual doubt.

H(enthaly)=E+PV

Differentiating,we get, $\Delta$ H = $\Delta$ E + $\Delta$ (PV)

=nC_vdT + P $\Delta$ V + V $\Delta$ P

=nC_vdT + nR $\Delta$ T + V $\Delta$ P

For isothermal process,dT=0, $\Delta$ T=0

hence, $\Delta$ H = 0 + 0 + V $\Delta$ P = V $\Delta$ P

BUT FOR ISOTHERMAL PROCESSES, IT IS SAID $\Delta$ U=0, $\Delta$ H=0

EXPLAIN!!!!!!!!!!!!!!!

Question

plz help.Conceptual doubt.

H(enthaly)=E+PV

Differentiating,we get, $\Delta$ H = $\Delta$ E + $\Delta$ (PV)

=nC_vdT + P $\Delta$ V + V $\Delta$ P

=nC_vdT + nR $\Delta$ T + V $\Delta$ P

For isothermal process,dT=0, $\Delta$ T=0

hence, $\Delta$ H = 0 + 0 + V $\Delta$ P = V $\Delta$ P

BUT FOR ISOTHERMAL PROCESSES, IT IS SAID $\Delta$ U=0, $\Delta$ H=0

EXPLAIN!!!!!!!!!!!!!!!

Naveen Kumar · Answer

H=U=PV
differentiating,
dH=dU+d(PV)
put PV=nRT
dH=dU+nRdT
Now if the process is isotermal,
dT=0
and if dU=0
then dH=0
.......................................................................................................................................................................................................

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plz help.Conceptual doubt. H(enthaly)=E+PV Differentiating,we get, H = E + (PV) =nC v dT + P V + V P =nC v dT + nR T + V P For isothermal process,dT=0, T=0 hence, H = 0 + 0 + V P = V P BUT FOR ISOTHERMAL PROCESSES, IT IS SAID U=0, H=0 EXPLAIN!!!!!!!!!!!!!!!

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