Please tell above answer quickly and as soon as possible ........................

Question

Samyak Jain · Answer

RMS speed of ideal gas molecules is , where T is the temperature in kelvin, R is universal gas constant, M is the molar mass of gas. ratio of rms speeds of molecules at T 2 and T 1 is = …..(1) Now, we need to compute temperatures T 1 and T 2 . We know that for isotherm, PV = constant i.e. PV = nRT and T is constant. Consider isotherm at T 1 . It is passing through P = 1.10 5 Pa and V = 1 m 3 . So, 1.10 5 Pa . 1 m 3 = nR T 1 or T 1 = (10 5 / nR) K Similarly, for T 2 , P = 2.10 5 Pa and V = 2 m 3 . So, 2.10 5 Pa . 2 m 3 = nR T 2 or T 2 = (4.10 5 / nR) K Substitute value of T 1 and T 2 in (1) and you will get ratio of rms speeds = = 2 .

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Please tell above answer quickly and as soon as possible ........................

Please tell above answer quickly and as soon as possible ........................

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Thermal Physics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship