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Please solve someone this question of calorimetry. Ask IITians is really helping me so much. I just love it.

Please solve someone this question of calorimetry. Ask IITians is really helping me so much. I just love it.

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Grade:12th pass

1 Answers

Arun
25763 Points
2 years ago
Given Electrical Power = 2 kilowatt = 2000 w
The efficiency of the heater is 80%
We know that The Heat energy in joules (J) is equal to the Electric power P in watts (W), times the time period t in seconds (s):
In unit time Heat energy = Electric Energy
So the Heat energy absorbed by the water is J
We know that,
....equation-1
Mass of the water (m) = 100 cc/sec = 100 g/sec
Specific heat capacity of water =j/gm
Temperature difference  Where  is the final temperature and  is the initial temperature of water. 
Therefore,
 
The outlet temperature will be 13.8 °C
 

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