Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
        Please post the above answer quickly and as soon as possible..............................
one month ago

Samyak Jain
284 Points
							Efficiency of Carnot heat engine depends on temperatures of source and sink and also depends on working substance.Efficiency of Carnot cycle, $\eta$ = (Work done) / (Heat supplied) = W / q1From first law of thermodynamics, q = $\dpi{80} \Delta$U + W.Since Carnot cycle is a cyclic process, $\dpi{80} \Delta$U = 0 i.e. q = W = Heat absorbed by system = q1 – q2where q2 = heat given out to the sink.$\dpi{80} \therefore$ $\eta$ = (q1 – q2)/ q1 = 1 – q2/q1 .Also, 1 – T2 / T1.Hence, we can say that efficiency of Carnot heat engine is independent of thermal capacity of source or sink.

one month ago
Samyak Jain
284 Points
							A point was missed out in above answer that 100% efficiency cannot be achieved in any of the process.But Carnot cycle is a process which can be most efficient.

one month ago
Think You Can Provide A Better Answer ?

Other Related Questions on Thermal Physics

View all Questions »

Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions