# Please post the above answer quickly and as soon as possible..............................

Samyak Jain
333 Points
3 years ago
Efficiency of Carnot heat engine depends on temperatures of source and sink and also depends on working substance.
Efficiency of Carnot cycle, $\eta$ = (Work done) / (Heat supplied) = W / q1
From first law of thermodynamics, q = $\dpi{80} \Delta$U + W.
Since Carnot cycle is a cyclic process, $\dpi{80} \Delta$U = 0 i.e. q = W = Heat absorbed by system = q1 – q2
where q2 = heat given out to the sink.
$\dpi{80} \therefore$ $\eta$ = (q1 – q2)/ q1 = 1 – q2/q1 .
Also, 1 – T2 / T1.
Hence, we can say that efficiency of Carnot heat engine is independent of thermal capacity of source or sink.
Samyak Jain
333 Points
3 years ago
A point was missed out in above answer that 100% efficiency cannot be achieved in any of the process.
But Carnot cycle is a process which can be most efficient.