Please answer this question with explanation... T

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Please answer this question with explanation... The internal energy of an ideal gas is related as U=a+b(PV).( where P is pressure of gas and V is volume of gas , a and b are constants of appropriate dimensions.Then find the Y(gamma) value of gas.1)a/b.2)1+(b/a)3)1 + (1/a).4) 1+ (1/b)

Vikas TU · Accepted Answer

U=a+b(PV)At constant volume,Cv =(∂ U/∂ T)vordU = Cv dTdU = bP dV (at constant volume)Thus, CvdT = bPdPintegrating both sides, we getCv * T = bP^2/2orCv = bP^2/2T...............................(1)At constant Pressure,dU/dV = Cp = 0 + bPand from Cp =(∂ U/∂ T)pordU = Cp dTdU = 0 + bPorbVdv = Cp dTintegerating both sides we get,b*V^2/2 = Cp*TorCp = bV^2/2T...................(2)From eqns. (1) and (2)Y = Cp/Cv = (bV^2/2T)/(bP^2/2T)= bV^2/bP^2= (V/P)^2

Thermal Physics> Please answer this question with explanat...

Please answer this question with explanation... The internal energy of an ideal gas is related as U=a+b(PV).( where P is pressure of gas and V is volume of gas , a and b are constants of appropriate dimensions.Then find the Y(gamma) value of gas.1)a/b.2)1+(b/a)3)1 + (1/a).4) 1+ (1/b)

Rahul , 8 Years ago

Vikas TU

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Thermal Physics> Please answer this question with explanat...

Please answer this question with explanation... The internal energy of an ideal gas is related as U=a+b(PV).( where P is pressure of gas and V is volume of gas , a and b are constants of appropriate dimensions.Then find the Y(gamma) value of gas.1)a/b.2)1+(b/a)3)1 + (1/a).4) 1+ (1/b)

Rahul , 8 Years ago

Vikas TU

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