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one week left for my board exams.... so
PLEASE ANSWER
In kirchoff's law of heat radiations it has been said that the ratio of spectral emissive power to the spectral absorptive power ( both corresp. to a wavelength ) at same temperature is same for all bodies and is equal to the spectral emissive power of a black body corresp. to same wavelength at that temperature.
e / a = E
This proves that emissive power absorptive power (at same temp.)
But while citing examples, books tell us the example of sodium vapour which when absorbs the light of same wavelength ( when light form some source at higher temperature is allowed to pass through it when cold ) as it would have emitted when excited.
and many more examples where the temp. of absorption is not equal to that of emission... WHY THIS CONDITION STATED IN THE LAW IS NOT OBEYED ??? OR AM I WRONG IN UNDERSTANDING THE LAW ???

Radhika Batra , 11 Years ago
Grade 11
anser 1 Answers
Askiitians Tutor Team

Last Activity: 14 Days ago

It's great that you're diving deep into Kirchhoff's law of heat radiation, especially with your board exams approaching. Let's clarify this concept and address your concerns about the relationship between emissive power and absorptive power.

Understanding Kirchhoff's Law

Kirchhoff's law states that for any body in thermal equilibrium at a given temperature, the ratio of its spectral emissive power (e) to its spectral absorptive power (a) at a specific wavelength is constant and equal to the spectral emissive power of a black body (E) at that same wavelength and temperature. This can be expressed mathematically as:

e / a = E

This law essentially means that good emitters of radiation are also good absorbers at thermal equilibrium. A black body, which is an idealized physical object, perfectly absorbs all incident radiation and emits radiation at the maximum possible intensity for any given temperature.

Clarifying the Misunderstanding

Your confusion seems to stem from examples like sodium vapor, where the conditions of absorption and emission are not at the same temperature. It's important to note that Kirchhoff's law applies specifically to bodies in thermal equilibrium. When we discuss sodium vapor absorbing light, we're often looking at a situation where the vapor is not in thermal equilibrium with the light source.

Examples of Non-Equilibrium Conditions

  • Sodium Vapor: When sodium vapor absorbs light from a hotter source, it can emit light of the same wavelength when it returns to a lower energy state. However, this process does not violate Kirchhoff's law because the sodium vapor is not in thermal equilibrium with the light source.
  • Gases in Spectroscopy: In spectroscopy, gases can absorb and emit light at specific wavelengths, but the temperatures of absorption and emission can differ significantly. This is due to the excitation states of the atoms or molecules involved, which can lead to emission at different temperatures.

Thermal Equilibrium vs. Non-Equilibrium

In thermal equilibrium, all parts of the system are at the same temperature, and Kirchhoff's law holds true. However, in many practical situations, such as in the examples you mentioned, the systems are not in equilibrium. The sodium vapor may be at a lower temperature than the light source, which allows it to absorb energy without being in thermal equilibrium.

Thus, while Kirchhoff's law provides a fundamental principle regarding the relationship between emissive and absorptive powers, it is crucial to apply it within the context of thermal equilibrium. When you encounter examples that seem to contradict this law, remember that they often involve non-equilibrium conditions where the law does not apply directly.

Final Thoughts

In summary, Kirchhoff's law is a powerful tool for understanding thermal radiation, but it is essential to recognize the conditions under which it applies. Your understanding is on the right track; just keep in mind the importance of thermal equilibrium when discussing emissive and absorptive powers. Good luck with your studies and your upcoming exams!

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