help@askiitians.com

+91-87964 74404

Grade 11Thermal Physics

One mole of a diatomic gas is heated under “ Kibolinsky Process” in which gas pressure is temperture controlled according to law P=4/5*CT^(3/2) . Where C is Kibolinsky constant. In this process, gas is heated by 300 K temperature.Answer the following question: The molar specific heat of the gas?

Pranav Sinha

12 Years agoGrade 11

1 Answer

Debojyoti Chaki

9 Years ago

Answer is 2RHow?Sol.P=4/5CT^3/2......(1)(PV)^3/2=(nRT)^3/2.......(2)(1)/(2)= P(V^3/2)=const........n=3C=R/gama-1+R/1-nPutting the values we get C=2R.

A container filled with a sample of an Idea gas at the pressure of 1.5atm. the gas is compressed isothermal ly to one fourth of its original volume. What is the new pressure of the gas?

thermal physics

1 Answer Available

Last Activity: 3 Years ago

how do we know the electric field due to an electric dipole of dipole moment P at distance r from the centre of dipole is fiven by .. where theta is angle between p amd r vector..

thermal physics

1 Answer Available

Last Activity: 4 Years ago

A A mole of helium gas initially at stp undergoes an isovolumetric process in which its pressure falls to half its initial value. The work done by gas is

thermal physics

1 Answer Available

Last Activity: 4 Years ago

5000 J of heat are added to two moles of an ideal monatomic gas, initially at a temperature of 500 K, while the gas performs 7500 J of work. What is the final temperature of the gas? step by step please

thermal physics

1 Answer Available

Last Activity: 4 Years ago

Please help me with the answer of this question related to radiation graph

thermal physics

1 Answer Available

Last Activity: 4 Years ago

View all Questions