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ONE GRAM OF STEAM AT 100 DEGREE CELSIUS SENT INTO ONE GRAM OF ICE AT 0 DEGREE CELSIUS THEN FINAL CONDITION OF MIXTURE IS

ONE GRAM OF STEAM AT 100 DEGREE CELSIUS SENT INTO ONE GRAM OF ICE AT 0 DEGREE CELSIUS THEN FINAL CONDITION OF MIXTURE IS

Grade:10

1 Answers

Arun
25758 Points
3 years ago
 

in this mixing problem

Heat is lost by 100 C steam = Heat gained by 0 C ice

heat gained by ice = m*Lice+m*Swater*(tf - 0)

                            = 1*80 + 1*1*tf

Heat lost by steam = m*Lwater + m*Swater *(100 - tf)

                            = 1*0.5 + 1*1 *(100 - tf)

t= 10.5 C

Note: All Units are in cgs

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