# In thermodynamic process the pressure of a fixed mass of of a gas is changed such that the gas releases 20 j  of heat and 8 J work is done on the gas. If the initial internal energy of the gas was 30 J then the final internal and will be

Mahima Kanawat
1010 Points
3 years ago
Dear student
$\Delta Q = \partial U+ \Delta W$
-20 = (Uf - Ui) + (+8)
-28 = U- 30
U= 2 J
WITH REGARDS
MAHIMA