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In the isothermal expansion of 10g of gas from volume V to 2V the work done by the gas is 575J. What is the root mean square speed of the molecules of the gas at that temperature ?

In the isothermal expansion of 10g of gas from volume V to 2V the work done by the gas is 575J. What is the root mean square speed of the molecules of the gas at that temperature ?

Grade:12

1 Answers

Vikas TU
14149 Points
5 years ago
In  isothermal expansion work done is given as:
W = nRTln(Vf/Vi) 
  = nRTln(2v/v)
  = nRTln2
575 = nRTln2
T = 575/nRln2......................(1)
 
Root Mean Square Method:
Vrms = root(3*R*575/w*Rln2)
put w = 10 gm as  mentioned.

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