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In given diatomic gas sound travels at 300m/sec. The root mean square velocity of the molecules of the gas is
a)4m/sec.
b)40m/sec
c)438m/sec
d)43900m/sec

Karan Shinde , 10 Years ago
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anser 3 Answers
Aziz Alam
v=\sqrt{\gamma P/\rho } velocity of sound in a gas

PM=\rho RT

P/\rho =RT/M

\Rightarrow v=\sqrt{\gamma RT/M}

\Rightarrow RT/M=v^{2}/\gamma

V_{rms}=\sqrt{3RT/M}

\Rightarrow V_{rms}=\sqrt{3v^{2}/\gamma }

Vrms=439.155 m/s

Last Activity: 10 Years ago
Aziz Alam
[v=\sqrt{\gamma P/\rho }] velocity of sound in a gas

PM=\rho RT

P/\rho =RT/M

\Rightarrow v=\sqrt{\gamma RT/M}

\Rightarrow RT/M=v^{2}/\gamma

V_{rms}=\sqrt{3RT/M}

\Rightarrow V_{rms}=\sqrt{3v^{2}/\gamma }

Vrms=439.155 m/s
ApprovedApproved
Last Activity: 10 Years ago
Karan Shinde
thank you.
 
Last Activity: 10 Years ago
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