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Grade 12Thermal Physics

in a motorcycle engine, after combustion occurs in the top of the cylinder, the portion is forced down as a mixture of gaseous products undergoes in adiabatic expansion. find the average power involved in this expansion when the engine is running at 80km/hr, assuming that the pressure immediately after combustion is at the initial volume is 60cm³, and the volume of the mixture at the botton of the store is 300cm³. assure that the gases are diatomic and that the time involved in the expansion is one half that of the total cycle.

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4 Years agoGrade 12
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ApprovedApproved Tutor Answer11 Months ago

To determine the average power involved in the adiabatic expansion of gases in a motorcycle engine, we need to break down the problem step by step. We'll use the given parameters: the initial volume after combustion, the final volume at the bottom of the stroke, the speed of the motorcycle, and the nature of the gases involved. Let's dive into the calculations.

Understanding the Parameters

We have the following information:

  • Initial Volume (V1): 60 cm³ (0.00006 m³)
  • Final Volume (V2): 300 cm³ (0.0003 m³)
  • Speed of Motorcycle: 80 km/hr (which we will convert to m/s)
  • Nature of Gases: Diatomic (like nitrogen and oxygen, which have a specific heat ratio, γ = 1.4)
  • Time for Expansion: Half of the total cycle time

Converting Speed to Meters per Second

First, let's convert the speed of the motorcycle from kilometers per hour to meters per second:

80 km/hr = (80 * 1000 m) / (3600 s) = 22.22 m/s

Calculating the Total Cycle Time

The total cycle time for a four-stroke engine is typically the time it takes for the engine to complete one full cycle of intake, compression, power, and exhaust. For simplicity, let's assume the engine runs at a constant speed and the cycle time can be estimated based on the engine's RPM (revolutions per minute). However, since we don't have the RPM, we will focus on the expansion time.

Adiabatic Expansion and Work Done

In an adiabatic process, the work done (W) during the expansion can be calculated using the formula:

W = (P1 * V1) / (γ - 1) * [(V2^(1-γ) - V1^(1-γ))]

Where:

  • P1 is the pressure after combustion (which we need to assume or calculate based on the engine's specifications).
  • V1 is the initial volume.
  • V2 is the final volume.
  • γ is the specific heat ratio (1.4 for diatomic gases).

Assuming Initial Pressure

Let's assume an initial pressure (P1) of 2 MPa (which is a reasonable estimate for combustion pressure in a motorcycle engine). Now we can plug in the values:

W = (2,000,000 Pa * 0.00006 m³) / (1.4 - 1) * [(0.0003^(1-1.4) - 0.00006^(1-1.4))]

Calculating Work Done

Now, let's calculate the work done:

W = (120 Pa*m³) / 0.4 * [(0.0003^(-0.4) - 0.00006^(-0.4))]

Calculating the terms:

0.0003^(-0.4) ≈ 7.37 and 0.00006^(-0.4) ≈ 15.85

Thus, W ≈ (120 / 0.4) * (7.37 - 15.85) ≈ 300 * (-8.48) ≈ -2544 J

Since work done is a positive quantity, we take the absolute value: W ≈ 2544 J.

Average Power Calculation

Power (P) is defined as work done over time. Since we assumed that the time for expansion is half of the total cycle time, we need to estimate the total cycle time. For a motorcycle engine running at 22.22 m/s, let’s assume a cycle time of 0.1 seconds (which is a rough estimate based on typical engine speeds).

Thus, the time for expansion (t) = 0.1 s / 2 = 0.05 s.

Now, we can calculate the average power:

P = W / t = 2544 J / 0.05 s = 50880 W or approximately 50.88 kW.

Final Thoughts

The average power involved in the adiabatic expansion of the gases in the motorcycle engine, under the given assumptions, is approximately 50.88 kW. This calculation illustrates how the principles of thermodynamics apply to real-world engine performance, showcasing the relationship between pressure, volume, and work done during the combustion cycle.