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Thermal Physics> If temperature of a back body increases f...

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If temperature of a back body increases from 7⁰C to 287⁰C, then the rate of energy radiation becomes:

2 times

16 times

4 times

(287/7)⁴

Indrani , 8 Years ago

Grade 12

3 Answers

Eshan

Last Activity: 6 Years ago

$T_1=7^{\circ}C=280K$
$T_2=287^{\circ}C=560K$

Rate of energy radiation $\propto T^4$

Hence the rate of energy radiation becomes $(\dfrac{560}{280})^4=2^4=16$ times.

Gitanjali Rout

Last Activity: 6 Years ago

$T_1=7^{\circ}C=280K$
$T_2=287^{\circ}C=560K$

Rate of energy radiation $\propto T^4$

Hence the rate of energy radiation becomes $(\dfrac{560}{280})^4=2^4=16$ times

so hope that you find the answer useful.

Khimraj

Last Activity: 6 Years ago

Rate of energy radiation is directly proportional to T⁴

where T is temperature

THen the rate of energy radiation become (560//280)⁴ = 16 times.

Hope it clears.

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